# NCERT Solutions for Class 12 Maths Maths Part-2 Chapter 10 Vector Algebra

Free NCERT Solutions for Class 12 Maths Chapter 10 Vector Algebra solved by Expert Teachers as per NCERT (CBSE) Book guidelines and brought to you by Toppers Bulletin. These Vector Algebra Exercise Questions with Solutions for Class 12 Maths covers all questions of Chapter Vector Algebra Class 12 and help you to revise complete Syllabus and Score More marks as per CBSE Board guidelines from the latest NCERT book for class 12 maths. You can read and download NCERT Book Solution to get a better understanding of all topics and concepts

10.1 Introduction

10.2 Some Basic Concepts

10.3 Types of Vectors

10.4 Addition of Vectors

10.5 Multiplication of a Vector by a Scalar

10.5.1 Components of a vector

10.5.2 Vector joining two points

10.5.3 Section formula

10.6 Product of Two Vectors

10.6.1 Scalar (or dot) product of two vectors

10.6.2 Projection of a vector on a line

10.6.3 Vector (or cross) product of two vectors.

## Vector Algebra NCERT Solutions – Class 12 Maths

**Exercise 10.1 :** Solutions of Questions on Page Number **: 428**

**Q1 : ****Represent graphically a displacement of 40 km, 30° east of north.
**

**Answer :**

Here, vector represents the displacement of 40 km, 30° East of North.

**Q2 : Classify the following measures as scalars and vectors.**

**(i) 10 kg (ii) 2 metres north-west (iii) 40°**

**(iv) 40 watt (v) 10-19 coulomb (vi) 20 m/s2**

**Answer :**

(i) 10 kg is a scalar quantity because it involves only magnitude.

(ii) 2 meters north-west is a vector quantity as it involves both magnitude and direction.

(iii) 40° is a scalar quantity as it involves only magnitude.

(iv) 40 watts is a scalar quantity as it involves only magnitude.

(v) 10-^{19} coulomb is a scalar quantity as it involves only magnitude.

(vi) 20 m/s^{2} is a vector quantity as it involves magnitude as well as direction.

**Q3 : Classify the following as scalar and vector quantities.**

**(i) time period (ii) distance (iii) force**

**(iv) velocity (v) work done**

**Answer :**

(i) Time period is a scalar quantity as it involves only magnitude.

(ii) Distance is a scalar quantity as it involves only magnitude.

(iii) Force is a vector quantity as it involves both magnitude and direction.

(iv) Velocity is a vector quantity as it involves both magnitude as well as direction.

(v) Work done is a scalar quantity as it involves only magnitude.

**Q4 : In Figure, identify the following vectors.**

**(i) Coinitial (ii) Equal (iii) Collinear but not equal**

**Answer :
(i)** Vectors and are coinitial because they have the same initial point.

**(ii)**Vectorsandare equal because they have the same magnitude and direction.

**(iii)**Vectorsand are collinear but not equal. This is because although they are parallel, their directions are not the same.

**Q5 : Answer the following as true or false.**

**(i) andare collinear.**

**(ii) Two collinear vectors are always equal in magnitude.**

**(iii) Two vectors having same magnitude are collinear.**

**(iv) Two collinear vectors having the same magnitude are equal.**

**Answer :**

(i) True.

Vectors andare parallel to the same line.

(ii) False.

Collinear vectors are those vectors that are parallel to the same line.

(iii) False.

It is not necessary for two vectors having the same magnitude to be parallel to the same line.

(iv) False.

Two vectors are said to be equal if they have the same magnitude and direction, regardless of the positions of their initial points.

**Exercise 10.2 :** Solutions of Questions on Page Number** : 440**

**Q1 : Compute the magnitude of the following vectors:**

**Answer :**

The given vectors are:

**Q2 : Write two different vectors having same magnitude.**

**Answer :**

Hence, are two different vectors having the same magnitude. The vectors are different because they have different directions.

**Q3 : Write two different vectors having same direction.**

**Answer :**

The direction cosines of are the same. Hence, the two vectors have the same direction.

**Q4 : Find the values of x and y so that the vectors are equal**

**Answer :**

The two vectors will be equal if their corresponding components are equal.

Hence, the required values of x and y are 2 and 3 respectively.

**Q5 : Find the scalar and vector components of the vector with initial point (2, 1) and terminal point (-5, 7).**

**Answer :**

The vector with the initial point P (2, 1) and terminal point Q (-5, 7) can be given by,

Hence, the required scalar components are â€“7 and 6 while the vector components are

**Q6 : Find the sum of the vectors.**

**Answer :**

The given vectors are.

**Q7 : Find the unit vector in the direction of the vector.**

**Answer :**

The unit vector in the direction of vector is given by.

**Q8 : Find the unit vector in the direction of vector, where P and Q are the points**

**(1, 2, 3) and (4, 5, 6), respectively.**

**Answer :
**The given points are P (1, 2, 3) and Q (4, 5, 6).

Hence, the unit vector in the direction of is.

**Q9 : For given vector and ****,find the unit vector in the direction of vector **

**Answer : **The given vector are and

Hence the unit vector in the direction

.

**Q10 : Find a vector in the direction of vector which has magnitude 8 units.**

**Answer :**

Hence, the vector in the direction of vector which has magnitude 8 units is given by,

**Q11 : Show that the vectorsare collinear.**

**Answer :**

Hence, the given vectors are collinear.

**Q12 : Find the direction cosines of the vector**

**Answer :**

Hence, the direction cosines of

**Q13 : Find the direction cosines of the vector joining the points A (1, 2, -3) and B (-1, -2, 1) directed from A to B.**

**Answer :**

The given points are A (1, 2, â€“3) and B (â€“1, â€“2, 1).

Hence, the direction cosines of are

**Q14 : Show that the vector is equally inclined to the axes OX, OY, and OZ.**

**Answer :**

Therefore, the direction cosines of

Now, let α, ÃŽÂ², and ÃŽÂ³be the angles formed by with the positive directions of x, y, and z axes.

Then, we have

Hence, the given vector is equally inclined to axes OX, OY, and OZ.

**Q15 : Find the position vector of a point R which divides the line joining two points P and Q whose position vectors are respectively, in the ration 2:1**

**(i) internally**

**(ii) externally**

**Answer :**

The position vector of point R dividing the line segment joining two points

P and Q in the ratio m: n is given by:

Internally:

Externally:

Position vectors of P and Q are given as:

(i) The position vector of point R which divides the line joining two points P and Q internally in the ratio 2:1 is given by,

(ii) The position vector of point R which divides the line joining two points P and Q externally in the ratio 2:1 is given by,

**Q16 : Find the position vector of the mid point of the vector joining the points P (2, 3, 4) and Q (4, 1, – 2).**

**Answer :**

The position vector of mid-point R of the vector joining points P (2, 3, 4) and Q (4, 1, -2) is given by,

**Q17 : Show that the points A, B and C with position vectors,, respectively form the vertices of a right angled triangle.**

**Answer :**

Position vectors of points A, B, and C are respectively given as:

**Q18 : In triangle ABC which of the following is not true:**

**A.**

**B.**

**C.**

**D.**

**Answer :**

On applying the triangle law of addition in the given triangle, we have:

From equations (1) and (3), we have:

Hence, the equation given in alternative C is **incorrect.**

The correct answer is C.

**Q19 : If are two collinear vectors, then which of the following are incorrect:**

**A. , for some scalar ÃŽÂ»**

**B.**

**C. the respective components of are proportional**

**D. both the vectors have same direction, but different magnitudes**

**Answer :**

If are two collinear vectors, then they are parallel.

Therefore, we have:

(For some scalar ÃŽÂ»)

If ÃŽÂ» = ±1, then .

Thus, the respective components of are proportional.

However, vectors can have different directions.

Hence, the statement given in** D** is **incorrect.**

The correct answer is **D.**

**Exercise 10.3 :** Solutions of Questions on Page Number **: 447**

**Q1 : Find the angle between two vectorsandwith magnitudesand 2, respectively having.**

**Answer :**

It is given that,

Now, we know that.

Hence, the angle between the given vectors andis.

**Q2 : Find the angle between the vectors**

**Answer :**

The given vectors are.

Also, we know that.

**Q3 : Find the projection of the vectoron the vector.**

**Answer :**

Letand.

Now, projection of vectoronis given by,

Hence, the projection of vector onis 0.

**Q4 : Find the projection of the vectoron the vector.**

**Answer :**

Letand.

Now, projection of vectoronis given by,

**Q5 : Show that each of the given three vectors is a unit vector:**

**Also, show that they are mutually perpendicular to each other.**

**Answer :**

Thus, each of the given three vectors is a unit vector.

Hence, the given three vectors are mutually perpendicular to each other.

**Q6 : Findand, if.**

**Answer :**

**Q7 : Evaluate the product.**

**Answer :**

**Q8 : Find the magnitude of two vectors, having the same magnitude and such that the angle between them is 60° and their scalar product is.**

**Answer :**

Let θ be the angle between the vectors

It is given that

We know that.

**Q9 : Find, if for a unit vector.**

**Answer :**

**Q10 : Ifare such thatis perpendicular to, then find the value of ÃŽÂ».**

**Answer :**

Hence, the required value of ÃŽÂ» is 8.

**Q11 : Show that is perpendicular to, for any two nonzero vectors**

**Answer :**

Hence, andare perpendicular to each other.

**Q12 : If, then what can be concluded about the vector?**

**Answer :**

It is given that.

Hence, vectorsatisfyingcan be any vector.

**Q13 : If are unit vectors such that , find the value of .**

**Answer :**

It is given that .

From (1), (2) and (3),

**Q14 : If either vector, then. But the converse need not be true. Justify your answer with an example.**

**Answer :**

We now observe that:

Hence, the converse of the given statement need not be true.

**Q15 : If the vertices A, B, C of a triangle ABC are (1, 2, 3), (â€“1, 0, 0), (0, 1, 2), respectively, then find ∠ABC. [∠ABC is the angle between the vectorsand]**

**Answer :**

The vertices of ΔABC are given as A (1, 2, 3), B (â€“1, 0, 0), and C (0, 1, 2).

Also, it is given that ∠ABC is the angle between the vectorsand.

Now, it is known that:

**Q16 : Show that the points A (1, 2, 7), B (2, 6, 3) and C (3, 10, -1) are collinear.**

**Answer :**

The given points are A (1, 2, 7), B (2, 6, 3), and C (3, 10, -1).

Hence, the given points A, B, and C are collinear.

**Q17 : Show that the vectorsform the vertices of a right angled triangle.**

**Answer :**

Let vectors be position vectors of points A, B, and C respectively.

Now, vectorsrepresent the sides of ΔABC.

Hence, ΔABC is a right-angled triangle.

**Q18 : Ifis a nonzero vector of magnitude ‘a’ and ÃŽÂ» a nonzero scalar, then ÃŽÂ»is unit vector if**

**(A) ÃŽÂ» = 1 (B) ÃŽÂ» = â€“1 (C)**

**(D)**

**Answer :**

Vectoris a unit vector if.

Hence, vectoris a unit vector if.

The correct answer is D.

**Exercise 10.4 :** Solutions of Questions on Page Number **: 454**

**Q1 : Find, if and.**

**Answer :**

We have,

and

**Q2 : Find a unit vector perpendicular to each of the vector and, where and.**

**Answer :**

We have,

and

Hence, the unit vector perpendicular to each of the vectors

and is given by the relation,

**Q3 : If a unit vector makes an angleswith with and an acute angle θ with, then find θ and hence, the compounds of.**

**Answer :**

Let unit vector have (a1, a2, a3) components.

⇒

Since is a unit vector, .

Also, it is given that makes angleswith with , and an acute angle θ with

Then, we have:

Hence, and the components of are

**Q4 : Show that**

**Answer :**

**Q5 : Find ÃŽÂ» and ÃŽÂ¼ if .**

**Answer :**

On comparing the corresponding components, we have:

Hence,

**Q6 : Given that and. What can you conclude about the vectors?**

**Answer :**

Then,

**(i)** Either or, or

**(ii)** Either or, or

But, and cannot be perpendicular and parallel simultaneously.

Hence, or.

**Q7 : Let the vectors given as . Then show that**

**Answer :**

We have,

On adding (2) and (3), we get:

Now, from (1) and (4), we have:

Hence, the given result is proved.

**Q8 : If either or, then. Is the converse true? Justify your answer with an example.**

**Answer :**

Take any parallel non-zero vectors so that.

It can now be observed that:

Hence, the converse of the given statement need not be true

**Q9 : Find the area of the triangle with vertices A (1, 1, 2), B (2, 3, 5) and**

**C (1, 5, 5).**

**Answer :**

The vertices of triangle ABC are given as A (1, 1, 2), B (2, 3, 5), and

C (1, 5, 5).

The adjacent sidesand of ΔABC are given as:

Area of ΔABC

Hence, the area of ΔABC

**Q10 : Find the area of the parallelogram whose adjacent sides are determined by the vector .**

**Answer :**

The area of the parallelogram whose adjacent sides are is.

Adjacent sides are given as:

Hence, the area of the given parallelogram is

**Q11 : Let the vectors and be such that and, then is a unit vector, if the angle between and is**

**(A) (B) (C) (D)**

**Answer :**

It is given that.

We know that, where is a unit vector perpendicular to both and and θ is the angle between and.

Now, is a unit vector if.

Hence, is a unit vector if the angle between

and is.

The correct answer is B.

**Q12 : Area of a rectangle having vertices A, B, C, and D with position vectors and respectively is**

**(A) (B) **1

**(C) **2** (D)**4

**Answer :**

The position vectors of vertices A, B, C, and D of rectangle ABCD are given as:

The adjacent sides and of the given rectangle are given as:

**Exercise Miscellaneous :** Solutions of Questions on Page Number** : 458**

**Q1 : Write down a unit vector in XY-plane, making an angle of 30° with the positive direction of x-axis.**

**Answer :**

If is a unit vector in the XY-plane, then

Here, θ is the angle made by the unit vector with the positive direction of the x-axis.

Therefore, for θ = 30°:

Hence, the required unit vector is.

**Q2 : Find the scalar components and magnitude of the vector joining the points.**

**Answer :**

The vector joining the pointscan be obtained by,

Hence, the scalar components and the magnitude of the vector joining the given points are respectively

and.

**Q3 : A girl walks 4 km towards west, then she walks 3 km in a direction 30° east of north and stops. Determine the girl’s displacement from her initial point of departure.**

**Answer :**

Let O and B be the initial and final positions of the girl respectively.

Then, the girl’s position can be shown as:

Now, we have:

By the triangle law of vector addition, we have:

Hence, the girl’s displacement from her initial point of departure is.

**Q4 : If, then is it true that? Justify your answer.**

**Answer :**

Now, by the triangle law of vector addition, we have.

It is clearly known that represent the sides of ΔABC.

Also, it is known that the sum of the lengths of any two sides of a triangle is greater than the third side.

Hence, it is not true that.

**Q5 : Find the value of x for whichis a unit vector.**

**Answer :**

is a unit vector if.

Hence, the required value of x is.

**Q6 : Find a vector of magnitude 5 units, and parallel to the resultant of the vectors.**

**Answer :**

We have,

Letbe the resultant of.

Hence, the vector of magnitude 5 units and parallel to the resultant of vectors is

**Q7 : If, find a unit vector parallel to the vector.**

**Answer :**

We have,

Hence, the unit vector alongis

**Q8 : Show that the points A (1, -2, -8), B (5, 0, -2) and C (11, 3, 7) are collinear, and find the ratio in which B divides AC.**

**Answer :**

The given points are A (1, â€“2, â€“8), B (5, 0, â€“2), and C (11, 3, 7).

Thus, the given points A, B, and C are collinear.

Now, let point B divide AC in the ratio. Then, we have:

On equating the corresponding components, we get:

Hence, point B divides AC in the ratio

**Q9 : Find the position vector of a point R which divides the line joining two points P and Q whose position vectors areexternally in the ratio 1: 2. Also, show that P is the mid point of the line segment RQ.**

**Answer :**

It is given that.

It is given that point R divides a line segment joining two points P and Q externally in the ratio 1: 2. Then, on using the section formula, we get:

Therefore, the position vector of point R is.

Position vector of the mid-point of RQ =

Hence, P is the mid-point of the line segment RQ.

**Q10 : Show that the direction cosines of a vector equally inclined to the axes OX, OY and OZ are.**

**Answer :**

Let a vector be equally inclined to axes OX, OY, and OZ at angle α.

Then, the direction cosines of the vector are cos α, cos α, and cos α.

Hence, the direction cosines of the vector which are equally inclined to the axes are

**Q11 : Let and. Find a vector which is perpendicular to both and, and.**

**Answer :**

Let.

Since Is perpendicular to both and, we have:

Also, it is given that:

On solving (i), (ii), and (iii), we get:

Hence, the required vector is.

**Q12 : The scalar product of the vector with a unit vector along the sum of vectors and is equal to one. Find the value of.**

**Answer :**

Therefore, unit vector along is given as:

Scalar product of with this unit vector is 1.

Hence, the value of ÃŽÂ» is 1.

**Q13 : If are mutually perpendicular vectors of equal magnitudes, show that the vector is equally inclined to and.**

**Answer :**

Sincere mutually perpendicular vectors, we have

It is given that:

Let vector be inclined to at angles respectively.

Then, we have:

Now, as, .

Hence, the vector is equally inclined to.

**Q14 : Prove that, if and only if are perpendicular, given.**

**Answer :**

**Q15 : If θ is the angle between two vectors and , then only when**

**(A) (B)**

**(C) (D)**

**Answer :**

Let θ be the angle between two vectors and.

Then, without loss of generality, and are non-zero vectors so that.

It is known that.

Hence, when.

The correct answer is B.

**Q16 : Let and be two unit vectors andθ is the angle between them. Then is a unit vector if**

**(A) (B) (C) (D)**

**Answer :**

Let and be two unit vectors andθ be the angle between them.

Then, .

Now, is a unit vector if.

Hence, is a unit vector if.

The correct answer is D.

**Q17 : The value of is**

**(A) 0 (B) â€“1 (C) 1 (D) 3**

**Answer :**

The correct answer is C.

**Q18 : If θ is the angle between any two vectors and, then when θisequal to**

**(A) 0 (B) (C) (D) π**

**Answer :**

Let θ be the angle between two vectors and.

Then, without loss of generality, and are non-zero vectors, so that.

Hence, when θisequal to.

The correct answer is B.